Problem
Given an array nums
with n
objects colored red, white, or blue, sort them in-place so that objects of the same color are adjacent, with the colors in the order red, white, and blue.
We will use the integers 0
, 1
, and 2
to represent the color red, white, and blue, respectively.
You must solve this problem without using the library’s sort function.
Example 1: Input: nums = [2,0,2,1,1,0] Output: [0,0,1,1,2,2]
Example 2: Input: nums = [2,0,1] Output: [0,1,2]
Constraints:
n == nums.length
1 <= n <= 300
nums[i]
is either0
,1
, or2
.
Follow up: Could you come up with a one-pass algorithm using only constant extra space?
Solution
Two Pointer - O(n) time - O(1) space
- Use a variable to track current color to sort
- Start slow at i = 0
- Start fast at i = 1
- if slow is current color, move slow and fast
- if not
- move fast to find the next current color
- swap the two elements
- if not found, increment current color and continue
class Solution {
public:
void sortColors(vector<int>& nums) {
int currentColor = 0;
for (int slow = 0; slow < nums.size(); slow++) {
}
}
}