Problem

You are given an m x n integer grid accounts where accounts[i][j] is the amount of money the i​​​​​​​​​​​th​​​​ customer has in the j​​​​​​​​​​​th​​​​ bank. Return the wealth that the richest customer has.

A customer’s wealth is the amount of money they have in all their bank accounts. The richest customer is the customer that has the maximum wealth.

Example 1:

Input: accounts = [[1,2,3],[3,2,1]] Output: 6 Explanation**:** 1st customer has wealth = 1 + 2 + 3 = 6 2nd customer has wealth = 3 + 2 + 1 = 6 Both customers are considered the richest with a wealth of 6 each, so return 6.

Example 2:

Input: accounts = [[1,5],[7,3],[3,5]] Output: 10 Explanation: 1st customer has wealth = 6 2nd customer has wealth = 10 3rd customer has wealth = 8 The 2nd customer is the richest with a wealth of 10.

Example 3:

Input: accounts = [[2,8,7],[7,1,3],[1,9,5]] Output: 17

Constraints:

  • m == accounts.length
  • n == accounts[i].length
  • 1 <= m, n <= 50
  • 1 <= accounts[i][j] <= 100

Solution - O(n*m) time - O(1) space

class Solution {
public:
    int maximumWealth(vector<vector<int>>& accounts) {
        int maxWealth = 0;
		for (int i = 0; i < accounts.size(); i++) {
			int currentWealth = 0;
			for (int j = 0; j < accounts[i].size(); j++) {
				currentWealth += accounts[i][j];
            }
            maxWealth = max(currentWealth, maxWealth);
        }
        return maxWealth;
    }
};