Problem
You are given an m x n
integer grid accounts
where accounts[i][j]
is the amount of money the ith
customer has in the jth
bank. Return the wealth that the richest customer has.
A customer’s wealth is the amount of money they have in all their bank accounts. The richest customer is the customer that has the maximum wealth.
Example 1:
Input: accounts = [[1,2,3],[3,2,1]]
Output: 6
Explanation**:**
1st customer has wealth = 1 + 2 + 3 = 6
2nd customer has wealth = 3 + 2 + 1 = 6
Both customers are considered the richest with a wealth of 6 each, so return 6.
Example 2:
Input: accounts = [[1,5],[7,3],[3,5]] Output: 10 Explanation: 1st customer has wealth = 6 2nd customer has wealth = 10 3rd customer has wealth = 8 The 2nd customer is the richest with a wealth of 10.
Example 3:
Input: accounts = [[2,8,7],[7,1,3],[1,9,5]] Output: 17
Constraints:
m == accounts.length
n == accounts[i].length
1 <= m, n <= 50
1 <= accounts[i][j] <= 100
Solution - O(n*m) time - O(1) space
class Solution {
public:
int maximumWealth(vector<vector<int>>& accounts) {
int maxWealth = 0;
for (int i = 0; i < accounts.size(); i++) {
int currentWealth = 0;
for (int j = 0; j < accounts[i].size(); j++) {
currentWealth += accounts[i][j];
}
maxWealth = max(currentWealth, maxWealth);
}
return maxWealth;
}
};